A Force Of 500 N On An Object Of 2 Kg Displaces It By 3 M. Find The Work Done By The Force And The Objects Final Speed Assuming It Was Initially At Re
a force of 500 N on an object of 2 kg displaces it by 3 m. find the work done by the force and the objects final speed assuming it was initially at rest.
GIVEN:
F = 500 N
m = 2 kg
d = 3 m
FORMULA:
W = Fd
where:
W = Work, J, kg•m•m/s•s
F = Force, N, kg•m/s•s
d = distance, m
EQUATION:
W = Fd
F = ma
SOLUTION:
W = Fd
W = (500 N)(3 m)
W = (500 )(3 m)
W = 1500
W = 1500 J
ANSWER:
The work done by the force is 1500 J.
(NOTE: Im sorry. I do not how to get the final speed. I can only get the acceleration.)
Comments
Post a Comment