:Read Each Item Carefully And Supply The Required Imformation., A Bicycle Tire Was Inflated To A Pressure Of 3.74 Atm During Early Morning When The Te

:read each item carefully and supply the required imformation.

A bicycle tire was inflated to a pressure of 3.74 atm during early morning when the temperature was 15°C.At noontime,the temperature rose to 35° C what was the resulting pressure in the tire (assuming that its volume did not change)?show your computation..

 

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Problem:

A bicycle tire was inflated to a pressure of 3.74 atm during early morning when the temperature was 15°C.At noontime,the temperature rose to 35° C what was the resulting pressure in the tire (assuming that its volume did not change)?show your computation

Note: Kelvin = °C  + 273.15

K = 15 + 273.15 = 288.15 K

K = 35 + 273.15  = 308.15 K

Given Data:

P₁ (initial pressure) = 3.74 atm

T₁ (initial temperature) =  15°C or 288.15 K

P₂ (final pressure)  =  ? unknown

T₂  (final temperature) = 35°C  or 308.15 K

Solution:

Gay-Lussacs Law states that pressure is directly proportional to temperature when volume and amount of gas are constant.

Formula = P₁/T₁ = P₂/T₂, to solve for P₂, we use P₂ = P₁×T₂/T₁

P₂ = P₁×T₂/T₁

    = 3.74 atm × 308.15 K / 288.15 K   (cancel kelvin unit)

    = 1152.481 atm / 288.15

    = 3.999 or 4 atm

Answer:

4 atm was the resulting pressure