What Is The Value Of The Derivative For The Given F(T)=(2t-5)(3t+4), When T=1/2

What is the value of the derivative for the given f(t)=(2t-5)(3t+4), when t=1/2

 

f(t)=(2t-5)(3t+4), when t= 1/2

Solution:

f(1/2)=(2 1/2-5)(3 1/2+4)

f1/2=(2.5-5)(3.5-4)

*converted it to decimal

f1/2=(-2.5)(-0.5)

f1/2=1.25

f 0.5=1.25

f 0.5=1.25

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0.5 0.5

f=2.5